<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title>Bing: ARR Declaration Syntax JS</title><link>http://www.bing.com:80/search?q=ARR+Declaration+Syntax+JS</link><description>Search results</description><image><url>http://www.bing.com:80/s/a/rsslogo.gif</url><title>ARR Declaration Syntax JS</title><link>http://www.bing.com:80/search?q=ARR+Declaration+Syntax+JS</link></image><copyright>Copyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.</copyright><item><title>What is the meaning of arr [:] in assignment in numpy?</title><link>https://stackoverflow.com/questions/35713891/what-is-the-meaning-of-arr-in-assignment-in-numpy</link><description>Your question involves a mix of basic Python syntax, and numpy specific details. In many ways it is the same for lists, but not exactly. arr[:, 0] returns the 1st column of arr (a view), arr[:,0]=10 sets the values of that column to 10. arr[:] returns arr (alist[:] returns a copy of a list). arr[:]=arr2 performs an inplace replacement; changing the values of arr to the values of arr2. The ...</description><pubDate>Fri, 24 Apr 2026 12:22:00 GMT</pubDate></item><item><title>Understanding arr[::-1] in numpy. Is this a special case?</title><link>https://stackoverflow.com/questions/65704951/understanding-arr-1-in-numpy-is-this-a-special-case</link><description>The first element was not selected, which was expected. And if I change 0 to -1, i.e, if I try: arr[len(arr)-1: -1: -1] OR even arr[:-1:-1], I get an empty array. Apparently I get the reversed array view by: arr[::-1] Q: How is this working? If I do not specify the first two arguments how does it infer that it needs to continue till 0? In fact it is just interpreting that it needs to go till ...</description><pubDate>Mon, 20 Apr 2026 09:42:00 GMT</pubDate></item><item><title>How *(&amp;arr + 1) - arr is working to give the array size</title><link>https://stackoverflow.com/questions/67509601/how-arr-1-arr-is-working-to-give-the-array-size</link><description>10 You need to explore what the type of the &amp;arr expression is, and how that affects the + 1 operation on it. Pointer arithmetic works in 'raw units' of the pointed-to type; &amp;arr is the address of your array, so it points to an object of type, "array of 7 int".</description><pubDate>Tue, 21 Apr 2026 07:25:00 GMT</pubDate></item><item><title>What is the difference between *&amp;arr and *&amp;arr[0] in C++, if arr is an ...</title><link>https://stackoverflow.com/questions/60922094/what-is-the-difference-between-arr-and-arr0-in-c-if-arr-is-an-array</link><description>1 Suppose I have an array of integers called arr. I am trying to understand the distinction between *&amp;arr and *&amp;arr[0]. I read that in C++, arr is essentially a pointer to the first element in the array and &amp;arr is a pointer to the whole array. They both return the same address, I get this part.</description><pubDate>Wed, 22 Apr 2026 08:07:00 GMT</pubDate></item><item><title>c - What does *arr [] mean? - Stack Overflow</title><link>https://stackoverflow.com/questions/38280914/what-does-arr-mean</link><description>7 what does *arr[] mean? As standalone expression *arr[] is not valid. For variable definitions there are two meanings here, depending of the context in which such an expression appears: Variable definition with initialiser (as per the OP's snippet) Copy</description><pubDate>Fri, 24 Apr 2026 21:04:00 GMT</pubDate></item><item><title>How does *(&amp;arr + 1) - arr give the length in elements of array arr?</title><link>https://stackoverflow.com/questions/61237796/how-does-arr-1-arr-give-the-length-in-elements-of-array-arr</link><description>The trick is to use the expression (&amp;arr) [1] - arr to get the array arr size. Both arr and &amp;arr points to the same memory location, but they both have different types.</description><pubDate>Thu, 16 Apr 2026 13:43:00 GMT</pubDate></item><item><title>arrays - C++: What is the difference between ' arr ' and ' arr ...</title><link>https://stackoverflow.com/questions/52312807/c-what-is-the-difference-between-arr-and-arr</link><description>When you use arr in your function call, it will decay to a pointer to its first element, it's equal to &amp;arr[0]. It will have the type int*. If you use arr[i] (for any valid index i), then you pass the value of a single element of the array. It will have the type int. Since the function expects a pointer (when declaring an argument, int arr[] is equal to int* arr), passing plain arr will work ...</description><pubDate>Thu, 23 Apr 2026 14:03:00 GMT</pubDate></item><item><title>Why does i[arr] work as well as arr[i] in C with larger data types?</title><link>https://stackoverflow.com/questions/7181504/why-does-iarr-work-as-well-as-arri-in-c-with-larger-data-types</link><description>arr is declared as the array of 4 structures with each structure comprising of a char array of 1024 chars. arr is resolved as the pointer to the first element to this array of structures. When you increment arr by 1, this new pointer, will skip one whole structure ( the type to which it points ) and then points to the next element in the array.</description><pubDate>Tue, 21 Apr 2026 16:14:00 GMT</pubDate></item><item><title>Array increment positioning with respect to indexer in C - array [i ...</title><link>https://stackoverflow.com/questions/7595247/array-increment-positioning-with-respect-to-indexer-in-c-arrayi-vs-arrayi</link><description>In this example i = 3, so arr[3] = 40. It then increases the value from 40 to 41 .So arr[i]++ increments the value of this particular index and a[i++] first increments the index and then gives the value for this index.</description><pubDate>Mon, 20 Apr 2026 11:15:00 GMT</pubDate></item><item><title>.NET 8 Application, IIS ARR Reverse Proxy, and Azure AD: Internal ...</title><link>https://stackoverflow.com/questions/79598910/net-8-application-iis-arr-reverse-proxy-and-azure-ad-internal-redirect-uri-a</link><description>Logs show X-Forwarded-Proto header is missing, only X-ARR-SSL is present. Checked and disabled "Reverse rewrite host in response headers" in IIS ARR Proxy Settings, but the perceived scheme/host in application logs did not change.</description><pubDate>Fri, 17 Apr 2026 19:54:00 GMT</pubDate></item></channel></rss>