<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title>Bing: DateDiff Example Dataiku</title><link>http://www.bing.com:80/search?q=DateDiff+Example+Dataiku</link><description>Search results</description><image><url>http://www.bing.com:80/s/a/rsslogo.gif</url><title>DateDiff Example Dataiku</title><link>http://www.bing.com:80/search?q=DateDiff+Example+Dataiku</link></image><copyright>Copyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.</copyright><item><title>Difference of two date time in sql server - Stack Overflow</title><link>https://stackoverflow.com/questions/2116540/difference-of-two-date-time-in-sql-server</link><description>Is there any way to take the difference between two datetime in sql server? For example, my dates are 2010-01-22 15:29:55.090 2010-01-22 15:30:09.153 So, the result should be 14.063 seconds.</description><pubDate>Sat, 11 Apr 2026 00:13:00 GMT</pubDate></item><item><title>How to use DATEDIFF to return year, month and day?</title><link>https://stackoverflow.com/questions/1541570/how-to-use-datediff-to-return-year-month-and-day</link><description>How can I use DATEDIFF to return the difference between two dates in years, months and days in SQL Server 2005 DATEDIFF (date , date) How to result that: 2 year 3 month 10 day Can anyone complet...</description><pubDate>Fri, 17 Apr 2026 05:42:00 GMT</pubDate></item><item><title>Calculate difference between 2 date / times in Oracle SQL</title><link>https://stackoverflow.com/questions/1096853/calculate-difference-between-2-date-times-in-oracle-sql</link><description>You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on. SQL&gt; select oldest - creation from my_table; If your date is stored as character data, you have to convert it to a date type first. SQL&gt; select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual ...</description><pubDate>Mon, 20 Apr 2026 15:18:00 GMT</pubDate></item><item><title>sql server 2008 - DateDiff years into decimals - Stack Overflow</title><link>https://stackoverflow.com/questions/10411704/datediff-years-into-decimals</link><description>DATEDIFF(dd, @EndDateTime, i.mat_exp_dte)/365 Am confused now as to how to calculate this. Would i need to convert the DataDiff into a different data type?</description><pubDate>Wed, 15 Apr 2026 20:04:00 GMT</pubDate></item><item><title>SQL DateDiff without weekends and public holidays</title><link>https://stackoverflow.com/questions/34794713/sql-datediff-without-weekends-and-public-holidays</link><description>SQL DateDiff without weekends and public holidays Asked 10 years, 3 months ago Modified 5 years, 5 months ago Viewed 28k times</description><pubDate>Thu, 16 Apr 2026 14:19:00 GMT</pubDate></item><item><title>How to cast the interval of DateDiff function of the SQL in to Datetime ...</title><link>https://stackoverflow.com/questions/18354384/how-to-cast-the-interval-of-datediff-function-of-the-sql-in-to-datetime-data-typ</link><description>i have a query that uses DateDiff function of the SQL.The interval returns min, hour or days according to how i put it. I want to return a Datetime datatype instead of the resulting integer type as it does.</description><pubDate>Sat, 11 Apr 2026 08:55:00 GMT</pubDate></item><item><title>sql server - How to get difference of days/months/years (datediff ...</title><link>https://stackoverflow.com/questions/17833176/how-to-get-difference-of-days-months-years-datediff-between-two-dates</link><description>I am looking for a way to implement the SQLServer-function datediff in PostgreSQL. That is, this function returns the count (as a signed integer value) of the specified datepart boundaries crossed</description><pubDate>Fri, 17 Apr 2026 04:02:00 GMT</pubDate></item><item><title>SQL Datediff - find datediff between rows - Stack Overflow</title><link>https://stackoverflow.com/questions/5728602/sql-datediff-find-datediff-between-rows</link><description>SQL Datediff - find datediff between rows Asked 14 years, 11 months ago Modified 4 years, 11 months ago Viewed 40k times</description><pubDate>Thu, 16 Apr 2026 14:26:00 GMT</pubDate></item><item><title>date - DATEDIFF de SQL Server - Stack Overflow en español</title><link>https://es.stackoverflow.com/questions/391126/datediff-de-sql-server</link><description>Me encuentro trabajando con SQL Server 2014 y Oracle 19c, necesito obtener la diferencia en microsegundos, segundos, minutos y horas entre dos fechas que tienen un rango de tiempo (ejemplo del form...</description><pubDate>Mon, 13 Apr 2026 10:12:00 GMT</pubDate></item><item><title>sql server - datediff rounding - Stack Overflow</title><link>https://stackoverflow.com/questions/5131958/datediff-rounding</link><description>I have a db table in SQL Server which contains a start date for a project. On a web status page I want to show how many days/weeks/months the project has run, the units depending on the duration. So</description><pubDate>Fri, 17 Apr 2026 00:49:00 GMT</pubDate></item></channel></rss>