http://www.bing.com:80/search?q=Integral+Image+Computer+VisionSearch resultshttp://www.bing.com:80/s/a/rsslogo.gifhttp://www.bing.com:80/search?q=Integral+Image+Computer+VisionCopyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.https://math.stackexchange.com/questions/5126672/integration-by-parts-on-definite-integralI have an integral, $$ I = \int_a^b x f (x) dx $$ and I would like to express this in terms of $\int_a^b f (x) dx$ if possible, but I don't see how integration by parts will help here.Wed, 15 Apr 2026 20:25:00 GMThttps://math.stackexchange.com/questions/5118171/why-must-the-curve-of-an-integral-intersect-the-originThe other kind of integral you often encounter is the definite integral. This is the integral that is sometimes described as "the area under the curve" (although I would consider that an application of the definite integral, not a definition).Tue, 31 Mar 2026 01:45:00 GMThttps://math.stackexchange.com/questions/287076/what-is-the-integral-of-0The integral of 0 is C, because the derivative of C is zero. Also, it makes sense logically if you recall the fact that the derivative of the function is the function's slope, because any function f (x)=C will have a slope of zero at point on the function.Sun, 19 Apr 2026 00:25:00 GMThttps://math.stackexchange.com/questions/5129783/various-methods-for-integral-from-mit-integration-bee-2026-semifinalEncountering the integral $$ \int \frac {x^2-2} {\left (x^2+2\right) \sqrt {x^4+4}} d x, $$ from MIT integration 2026 Semifinal , I tried my best to finish it within the time limit. $$ \begin {aligned} ...Tue, 07 Apr 2026 10:19:00 GMThttps://math.stackexchange.com/questions/586107/what-is-the-difference-between-an-indefinite-integral-and-an-antiderivativeWolfram Mathworld says that an indefinite integral is "also called an antiderivative". This MIT page says, "The more common name for the antiderivative is the indefinite integral." One is free to define terms as you like, but it looks like at least some (and possibly most) credible sources define them to be exactly the same thing.Thu, 16 Apr 2026 18:29:00 GMThttps://math.stackexchange.com/questions/15294/why-is-the-area-under-a-curve-the-integralOne is the question of why the definite Riemann integral gives the correct notion of "area under a curve" for a (nonnegative, Riemann integrable) function. The other, which seems to be what you're really asking, is the question of why an antiderivative evaluated at the endpoints of an interval and subtracted yields that definite integral.Sat, 18 Apr 2026 05:05:00 GMThttps://math.stackexchange.com/questions/1242056/solving-the-integral-of-ex2The integral which you describe has no closed form which is to say that it cannot be expressed in elementary functions. For example, you can express $\int x^2 \mathrm {d}x$ in elementary functions such as $\frac {x^3} {3} +C$.Fri, 17 Apr 2026 23:50:00 GMThttps://math.stackexchange.com/questions/2567170/what-is-an-integralA different type of integral, if you want to call it an integral, is a "path integral". These are actually defined by a "normal" integral (such as a Riemann integral), but path integrals do not seek to find the area under a curve. I think of them as finding a weighted, total displacement along a curve.Sun, 19 Apr 2026 02:12:00 GMThttps://math.stackexchange.com/questions/5101304/can-the-integral-closure-of-a-ring-be-taken-intrinsicallyHowever, one "intrinsic integral closure" that is often used is the normalization, which in the case on an integral domain is the integral closure in its field of fractions. It's the maximal integral extension with the same fraction field as the original domain.Sun, 19 Apr 2026 02:05:00 GMThttps://math.stackexchange.com/questions/4099830/what-other-tricks-and-techniques-can-i-use-in-integrationSo far, I know and can use a reasonable number of 'tricks' or techniques when I solve integrals. Below are the tricks/techniques that I know for indefinite and definite integrals separately. Indef...Sun, 19 Apr 2026 15:20:00 GMT