<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title>Bing: Integral of Ramp Function</title><link>http://www.bing.com:80/search?q=Integral+of+Ramp+Function</link><description>Search results</description><image><url>http://www.bing.com:80/s/a/rsslogo.gif</url><title>Integral of Ramp Function</title><link>http://www.bing.com:80/search?q=Integral+of+Ramp+Function</link></image><copyright>Copyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.</copyright><item><title>calculus - Integration by parts on definite integral - Mathematics ...</title><link>https://math.stackexchange.com/questions/5126672/integration-by-parts-on-definite-integral</link><description>I have an integral, $$ I = \int_a^b x f (x) dx $$ and I would like to express this in terms of $\int_a^b f (x) dx$ if possible, but I don't see how integration by parts will help here.</description><pubDate>Sat, 21 Mar 2026 18:53:00 GMT</pubDate></item><item><title>Various methods for Integral from MIT Integration Bee 2026 Semifinal</title><link>https://math.stackexchange.com/questions/5129783/various-methods-for-integral-from-mit-integration-bee-2026-semifinal</link><description>Encountering the integral $$ \\int \\frac{x^2-2}{\\left(x^2+2\\right) \\sqrt{x^4+4}} d x, $$ from MIT integration 2026 Semifinal , I tried my best to finish it within the time limit. $$ \\begin{aligned} ...</description><pubDate>Sat, 28 Mar 2026 11:07:00 GMT</pubDate></item><item><title>solving the integral of $e^ {x^2}$ - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/1242056/solving-the-integral-of-ex2</link><description>The integral which you describe has no closed form which is to say that it cannot be expressed in elementary functions. For example, you can express $\int x^2 \mathrm {d}x$ in elementary functions such as $\frac {x^3} {3} +C$.</description><pubDate>Thu, 09 Apr 2026 23:24:00 GMT</pubDate></item><item><title>What does it mean for an "integral" to be convergent?</title><link>https://math.stackexchange.com/questions/5036475/what-does-it-mean-for-an-integral-to-be-convergent</link><description>The noun phrase "improper integral" written as $$ \int_a^\infty f (x) \, dx $$ is well defined. If the appropriate limit exists, we attach the property "convergent" to that expression and use the same expression for the limit.</description><pubDate>Wed, 08 Apr 2026 00:16:00 GMT</pubDate></item><item><title>What is the integral of 1/x? - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/206032/what-is-the-integral-of-1-x</link><description>Answers to the question of the integral of $\frac {1} {x}$ are all based on an implicit assumption that the upper and lower limits of the integral are both positive real numbers.</description><pubDate>Sun, 12 Apr 2026 05:12:00 GMT</pubDate></item><item><title>calculus - Is there really no way to integrate $e^ {-x^2 ...</title><link>https://math.stackexchange.com/questions/154968/is-there-really-no-way-to-integrate-e-x2</link><description>@user599310, I am going to attempt some pseudo math to show it: $$ I^2 = \int e^-x^2 dx \times \int e^-x^2 dx = Area \times Area = Area^2$$ We can replace one x, with a dummy variable, move the dummy copy into the first integral to get a double integral. $$ I^2 = \int \int e^ {-x^2-y^2} dA $$ In context, the integrand a function that returns ...</description><pubDate>Sun, 12 Apr 2026 03:11:00 GMT</pubDate></item><item><title>Why must the curve of an integral intersect the origin?</title><link>https://math.stackexchange.com/questions/5118171/why-must-the-curve-of-an-integral-intersect-the-origin</link><description>The other kind of integral you often encounter is the definite integral. This is the integral that is sometimes described as "the area under the curve" (although I would consider that an application of the definite integral, not a definition).</description><pubDate>Tue, 31 Mar 2026 01:45:00 GMT</pubDate></item><item><title>calculus - Understanding symmetry in a double integral - Mathematics ...</title><link>https://math.stackexchange.com/questions/4971458/understanding-symmetry-in-a-double-integral</link><description>Understanding symmetry in a double integral Ask Question Asked 1 year, 6 months ago Modified 1 year, 6 months ago</description><pubDate>Thu, 09 Apr 2026 23:53:00 GMT</pubDate></item><item><title>Can the integral closure of a ring be taken intrinsically?</title><link>https://math.stackexchange.com/questions/5101304/can-the-integral-closure-of-a-ring-be-taken-intrinsically</link><description>However, one "intrinsic integral closure" that is often used is the normalization, which in the case on an integral domain is the integral closure in its field of fractions. It's the maximal integral extension with the same fraction field as the original domain.</description><pubDate>Fri, 20 Mar 2026 13:18:00 GMT</pubDate></item><item><title>Evaluation of Gaussian integral $\\int_{0}^{\\infty} \\mathrm{e}^{-x^2} dx$</title><link>https://math.stackexchange.com/questions/9286/evaluation-of-gaussian-integral-int-0-infty-mathrme-x2-dx</link><description>Both formulas can be used for many special integrals like the Fresnel Integral or the Sinc Integral and much more. Note that one could directly derive this result from $\Gamma (1/2)$ by substitution, but the formula is far more powerful.</description><pubDate>Tue, 07 Apr 2026 07:20:00 GMT</pubDate></item></channel></rss>