<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title>Bing: Shape Code Drawing</title><link>http://www.bing.com:80/search?q=Shape+Code+Drawing</link><description>Search results</description><image><url>http://www.bing.com:80/s/a/rsslogo.gif</url><title>Shape Code Drawing</title><link>http://www.bing.com:80/search?q=Shape+Code+Drawing</link></image><copyright>Copyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.</copyright><item><title>python - What does .shape [] do in "for i in range (Y.shape [0 ...</title><link>https://stackoverflow.com/questions/10200268/what-does-shape-do-in-for-i-in-rangey-shape0</link><description>shape is a tuple that gives you an indication of the number of dimensions in the array. So in your case, since the index value of Y.shape[0] is 0, your are working along the first dimension of your array.</description><pubDate>Sun, 26 Apr 2026 16:16:00 GMT</pubDate></item><item><title>Difference between numpy.array shape (R, 1) and (R,)</title><link>https://stackoverflow.com/questions/22053050/difference-between-numpy-array-shape-r-1-and-r</link><description>Shape n, expresses the shape of a 1D array with n items, and n, 1 the shape of a n-row x 1-column array. (R,) and (R,1) just add (useless) parentheses but still express respectively 1D and 2D array shapes, Parentheses around a tuple force the evaluation order and prevent it to be read as a list of values (e.g. in function calls).</description><pubDate>Wed, 22 Apr 2026 09:32:00 GMT</pubDate></item><item><title>arrays - what does numpy ndarray shape do? - Stack Overflow</title><link>https://stackoverflow.com/questions/47564495/what-does-numpy-ndarray-shape-do</link><description>yourarray.shape or np.shape() or np.ma.shape() returns the shape of your ndarray as a tuple; And you can get the (number of) dimensions of your array using yourarray.ndim or np.ndim(). (i.e. it gives the n of the ndarray since all arrays in NumPy are just n-dimensional arrays (shortly called as ndarray s)) For a 1D array, the shape would be (n,) where n is the number of elements in your array ...</description><pubDate>Mon, 20 Apr 2026 08:02:00 GMT</pubDate></item><item><title>python - x.shape [0] vs x [0].shape in NumPy - Stack Overflow</title><link>https://stackoverflow.com/questions/48134598/x-shape0-vs-x0-shape-in-numpy</link><description>On the other hand, x.shape is a 2-tuple which represents the shape of x, which in this case is (10, 1024). x.shape[0] gives the first element in that tuple, which is 10. Here's a demo with some smaller numbers, which should hopefully be easier to understand.</description><pubDate>Wed, 22 Apr 2026 08:28:00 GMT</pubDate></item><item><title>What does shape[0] and shape[1] do in python? - Stack Overflow</title><link>https://stackoverflow.com/questions/51455927/what-does-shape0-and-shape1-do-in-python</link><description>In python shape [0] returns the dimension but in this code it is returning total number of set. Please can someone tell me work of shape [0] and shape [1]? Code: m_train = train_set_x_orig.shape [0]</description><pubDate>Sat, 18 Apr 2026 16:11:00 GMT</pubDate></item><item><title>python - What does 'range (y.shape [1])' mean in "for i in range ...</title><link>https://stackoverflow.com/questions/65949568/what-does-rangey-shape1-mean-in-for-i-in-rangedataset2-shape1</link><description>I'm trying to find out how this above-mentioned piece of code works in a layman sense? for context, this code contains Numpy, Seaborn, Pandas and matplotlib. below is the line of code: dataset2 = d...</description><pubDate>Thu, 23 Apr 2026 13:13:00 GMT</pubDate></item><item><title>vba to add a shape at a specific cell location in Excel</title><link>https://stackoverflow.com/questions/16038893/vba-to-add-a-shape-at-a-specific-cell-location-in-excel</link><description>I am trying to add a shape at a specific cell location but cannot get the shape added at the desired location for some reason. Below is the code I am using to add the shape: Cells(milestonerow,</description><pubDate>Sat, 25 Apr 2026 12:14:00 GMT</pubDate></item><item><title>How to extract layer shape and type from ONNX / PyTorch?</title><link>https://stackoverflow.com/questions/71057613/how-to-extract-layer-shape-and-type-from-onnx-pytorch</link><description>I would like to 'translate' a PyTorch model to another framework (non-tf/keras). I'm trying to take a pytorch model, and automate the translation to the other framework, which contains similar type...</description><pubDate>Sun, 26 Apr 2026 12:05:00 GMT</pubDate></item><item><title>ValueError: Arguments `target` and `output` must have the same shape ...</title><link>https://stackoverflow.com/questions/78470683/valueerror-arguments-target-and-output-must-have-the-same-shape-received</link><description>Your labels have a shape of (16,), while your model's output has a shape of (None,3). Probably the issue is that your labels are not one-hot encoded. They should have the same second dimension as your output layer:</description><pubDate>Tue, 21 Apr 2026 23:31:00 GMT</pubDate></item><item><title>python - ValueError: shape mismatch: objects cannot be broadcast to a ...</title><link>https://stackoverflow.com/questions/16950074/valueerror-shape-mismatch-objects-cannot-be-broadcast-to-a-single-shape</link><description>ValueError: shape mismatch: objects cannot be broadcast to a single shape Asked 12 years, 10 months ago Modified 2 years, 3 months ago Viewed 300k times</description><pubDate>Fri, 24 Apr 2026 01:16:00 GMT</pubDate></item></channel></rss>