Sep 8, 2016 · The main difference between $\ce {Li+}$ and $\ce {Al^3+}$ is their charge. Aluminium has three times lithium’s charge. When calculating orbitals, the first step is to set up a Schrödinger …

Nov 5, 2015 · There are efforts underway to develop ionic liquids for the purpose of reducing bauxite using exotic intermediates such as aluminum fluoride. However, the aqueous $\\ce{Al^3+}$ ion is …

Aug 9, 2014 · No it does not. It is true that electrons repulse each other, however, they all are attracted towards the nucleus. The real 'size' of an atom or ion is a result of compromise between electron …

Jun 18, 2017 · Why is the product of $\ce {Al (OH)3 + NaOH -> Na [Al (OH)4]}$ and not $\ce {NaAlO3H2 + H2O}$? Is this an acid-base reaction?

Oct 26, 2013 · We could extend the acidic/basic nature of $\ce {Al2O3}$ to the Lewis acid/base theory. For more about this see this question which has been asked before: Recall the Lewis Theory of acids …

Apr 27, 2017 · I came across this question: Which of the following is bigger? $$\\ce{K+, Ca^2+, Al^3+, S^2-, Cl-}$$ Now, I know that the radius decreases as the period progresses to the right and …

Nov 20, 2023 · The equations written by Aleph are all wrong, mainly because they are not stoichiometrically correct. They should have been written $$\ce {Al^ {3+} + 6 H2O -> [Al (H2O)6]^ …

Oct 29, 2017 · $\ce {Al^3+}$ The chemical can be added to a solution to test for the presence of $\ce {Al^3+}$ ions. This is done by first adding $\ce {NaOH}$ to the solution to precipitate out $\ce {Al …

Nov 26, 2016 · Consider the size of the first s-orbital of $\ce {Mg}$. The nuclear charge is 12+. Therefore the first electrons, close to the nucleus, are attracted by a relatively large force. These first …

May 22, 2021 · Suppose that I wanted to electroplate Al(s) onto a Cu(s) Cathode, (using an Aluminium Nitrate solution and Al(s) anode). At standard conditions, Al(s) is the strongest reducing agent, which …