
combinations - How to map cubic pixels to a 2d grid maintaining ...
Jul 21, 2022 · That's only about twice $100$. The nearest you could get to a square pattern would be $12$ by $18$. I haven't thought about arranging the $216$ combinations as hexagons or …
graph theory - ILP formulation for finding best route in 18xx-style ...
May 16, 2025 · I'm working on an ILP formulation that's supposed to find the best scoring set of routes on a given turn in a 18xx-style board game (in this particular case, Shikoku 1889) Problem …
Radius, diameter and center of graph - Mathematics Stack Exchange
For this graph, there is only a single such vertex, so your center in the single vertex labelled $3$ in the graph. You can see that the name center really is quite aptly named. The vertices of the center …
Prove game Hex must have a winner - Mathematics Stack Exchange
Sep 28, 2021 · About 7 years ago I was asked this question. I remembered it right now, and I can't solve it. Prove that no matter how you play, the game Hex will have a winner at the end.
Method to solve probabilistic graph problem
6 days ago · Are you familiar with the probabilistic proof of Erdős's "high girth and high chromatic number" result? I don't know for certain that it will work, but a similar approach is the first thing I …
graph theory - Hexagonal coordinate system for labeling vertices that ...
Jul 24, 2019 · The units are just steps through the grid, right? i.e.if I can only hop from the center of one hexagon to the center of an adjacent hexagon, you want to count the number of hops to get from one …
User antonio grasso - Mathematics Stack Exchange
Mar 8, 2026 · Q&A for people studying math at any level and professionals in related fields
Formula for the points in a grid of hexagons.
Mar 13, 2018 · Say I fill up the plane with regular hexagons whose side is distance 1, all packed together. Is there a formula or a pattern that gives all points? I let the $(0,0)$ be the center of the first …
Mathematics Stack Exchange
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Application of Sperner's Lemma. - Mathematics Stack Exchange
Aug 8, 2022 · The triangle $ABC$ is divided into sub-simplices in a non-trivial way (there exists at least one point on each of the segments $AB$, $AC$, $BC$ other than $A$, $B ...