Nov 2, 2015 · Using SQL Server, how do I split a string so I can access item x? Take a string "Hello John Smith". How can I split the string by space and access the item at index 1 which should return …

The 3 parameters are the string to be split, the delimiter, and the part/substring number (starting from 1) to be returned. So if you have a field named string that contains stuff like AB_XXX and you would like …

PostgreSQL 14 will support negative index so it will be straightforward operation. split_part Splits string at occurrences of delimiter and returns the n'th field (counting from one), or when n is negative, …

Mar 30, 2009 · 33 You've tagged this SQL Server 2008 but future visitors to this question (using SQL Server 2016+) will likely want to know about STRING_SPLIT. With this new builtin function you can …

Dec 2, 2022 · Split_part () can take 3 arguments - string, delimiter, and part number. So you need to cross join with a numbers table that has all the integer values from 1 to the max number of parts in …

Sep 27, 2017 · 123 234 456 421 345 To remove anything after the "-", I tried using Select split_part (column name, '-', 1) from table_name and it worked. Do you know what I can use to remove …

SPLIT_PART with 2 delimiters with OR condition Snowflake Asked 4 years, 2 months ago Modified 4 years, 2 months ago Viewed 4k times

May 15, 2018 · Is there any way to use split_part on multiple delimiters? So for lower (trim (split_part (t.advisor_last_name,' ',1)) I would like to split advisor_last_name if either space (as shows) or …

Dec 11, 2020 · Need to split column value into multiple columns based on delimiter, Also need to create columns dynamically based on no. of delimiters, delimiter could be comma or so. Thanks,

I need to split these examples into City and Of-Style and Part1 and Part2. I figured out this little piece of code, but it switches part1 and part2 if the string contains a '-'.