Sep 26, 2015 · 6 nextLine () reads the remainder of the current line even if it is empty. Correct. nextInt () reads an integer but does not read the escape sequence "\n". Correct 1. next () reads the current line …

Jul 17, 2013 · System.out.println("Enter EmployeeName:"); ename=(scanner.nextLine()); This is because next () grabs only the next token, and the space acts as a delimiter between the tokens. By …

Java Scanner class reading strings Asked 16 years, 5 months ago Modified 9 years ago Viewed 159k times

May 11, 2011 · I'm writing a program that uses an Event class, which has in it an instance of a calendar, and a description of type String. The method to create an event uses a Scanner to take in a month, …

Nov 7, 2017 · Because method nextLine() reads next symbols from current current line after cursors current position. For example, if your input contains 2 line 1 and Hello World. And source like that: int …

This Scanner class comes under java.util, hence the first line of the program is import java.util.Scanner; which allows the user to read values of various types in Java.

Nov 13, 2015 · Learning to read compile errors will help you immensely. This is literally telling you that scanner has no method nextString. At that point, if you shoot on over to the java API for scanner you …

Apr 16, 2014 · 2 Scanner.next stops reading when it encounters a delimiter, which is a whitespace. Use the nextLine method instead.

Oct 5, 2015 · 0 If you use the nextLine () method immediately following the nextInt () method, recall that nextInt () reads integer tokens; because of this, the last newline character for that line of integer input …

Mar 24, 2010 · int n = Integer.parseInt(System.console().readLine()); The question is "How to read from standard input". A console is a device typically associated to the keyboard and display from which a …