http://www.bing.com:80/search?q=Continuous+Data+Statistical+Distribution+ChartSearch resultshttp://www.bing.com:80/s/a/rsslogo.gifhttp://www.bing.com:80/search?q=Continuous+Data+Statistical+Distribution+ChartCopyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.https://math.stackexchange.com/questions/5114829/continuous-vs-discrete-variablesBoth discrete and continuous variables generally do have changing values—and a discrete variable can vary continuously with time. I am quite aware that discrete variables are those values that you can count while continuous variables are those that you can measure such as weight or height.Sat, 28 Mar 2026 22:48:00 GMThttps://math.stackexchange.com/questions/5127388/proving-a-limit-of-a-measure-is-continuousI was trying to formalize some things about string motion in physics so I could answer more general questions about it and then I got to a point as to see the limit written below. I then asked myselfFri, 10 Apr 2026 13:00:00 GMThttps://math.stackexchange.com/questions/2343261/sequentially-continuous-implies-continuousI think we can show that the identity $ (X, \tau_X)$ to $ (X,\tau')$ is sequentially continuous, and it is certainly not continuous. So in a way, being a sequential space is the natural notion here to consider.Mon, 13 Apr 2026 14:15:00 GMThttps://math.stackexchange.com/questions/477/cardinality-of-set-of-real-continuous-functionsThe cardinality is at most that of the continuum because the set of real continuous functions injects into the sequence space $\mathbb R^N$ by mapping each continuous function to its values on all the rational points. Since the rational points are dense, this determines the function.Fri, 10 Apr 2026 09:47:00 GMThttps://math.stackexchange.com/questions/75491/how-does-the-existence-of-a-limit-imply-that-a-function-is-uniformly-continuousThen the theorem that says that any continuous function on a compact set is uniformly continuous can be applied. The arguments above are a workaround this.Sat, 11 Apr 2026 22:03:00 GMThttps://math.stackexchange.com/questions/254626/the-space-of-bounded-continuous-functions-is-not-separableThe space of bounded continuous functions is not separable Ask Question Asked 13 years, 4 months ago Modified 3 months agoSat, 11 Apr 2026 19:11:00 GMThttps://math.stackexchange.com/questions/3364/topological-properties-preserved-by-continuous-mapsYou'll find topological properties with indication of whether they are preserved by (various kinds of) continuous maps or not (such as open maps, closed maps, quotient maps, perfect maps, etc.). For mere continuous most things have been mentioned: simple covering properties (variations on compactness, connectedness, Lindelöf) and separability.Fri, 10 Apr 2026 13:00:00 GMThttps://math.stackexchange.com/questions/667939/is-the-set-of-non-differentiable-points-for-a-singular-continuous-function-nowheIn view of the correspondence of nondecreasing functions with positive measures, singular continuous functions correspond to singular continuous measures, i.e. an atomless positive Borel measures concentrated on a set of Lebesgue measure zero.Sat, 11 Apr 2026 14:17:00 GMThttps://math.stackexchange.com/questions/4853516/can-a-discontinuous-function-have-a-continuous-derivativeCan a discontinuous function have a continuous derivative? Ask Question Asked 2 years, 2 months ago Modified 2 years, 2 months agoWed, 08 Apr 2026 15:33:00 GMThttps://math.stackexchange.com/questions/775045/how-do-i-show-that-all-continuous-periodic-functions-are-bounded-and-uniform-conShow that every continuous periodic function is bounded and uniformly continuous. For boundedness, I first tried to show that since the a periodic function is continuous, it is continuous for the closed interval $ [x_0,x_0+P]$. I know that there is a theorem saying that if it is continuous on a closed interval, then it is bounded.Tue, 07 Apr 2026 12:06:00 GMT