<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title>Bing: Continuous Random Process</title><link>http://www.bing.com:80/search?q=Continuous+Random+Process</link><description>Search results</description><image><url>http://www.bing.com:80/s/a/rsslogo.gif</url><title>Continuous Random Process</title><link>http://www.bing.com:80/search?q=Continuous+Random+Process</link></image><copyright>Copyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.</copyright><item><title>Continuous vs Discrete Variables - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/5114829/continuous-vs-discrete-variables</link><description>Both discrete and continuous variables generally do have changing values—and a discrete variable can vary continuously with time. I am quite aware that discrete variables are those values that you can count while continuous variables are those that you can measure such as weight or height.</description><pubDate>Sat, 28 Mar 2026 22:48:00 GMT</pubDate></item><item><title>How to prove $\sin (1/x)$ is not uniformly continuous</title><link>https://math.stackexchange.com/questions/79649/how-to-prove-sin1-x-is-not-uniformly-continuous</link><description>In fact the author's statement is not clear, because by stating "is not uniformly continuous" one is assuming the function is in some underlying domain already. If it is an close interval with no singular points we may just apply Cantor's theorem.</description><pubDate>Tue, 21 Apr 2026 12:33:00 GMT</pubDate></item><item><title>Proof of Continuous compounding formula - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/539115/proof-of-continuous-compounding-formula</link><description>Following is the formula to calculate continuous compounding A = P e^(RT) Continuous Compound Interest Formula where, P = principal amount (initial investment) r = annual interest rate (as a</description><pubDate>Wed, 22 Apr 2026 06:12:00 GMT</pubDate></item><item><title>Understanding Lipschitz Continuity - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/2374289/understanding-lipschitz-continuity</link><description>I have heard of functions being Lipschitz Continuous several times in my classes yet I have never really seemed to understand exactly what this concept really is. Here is the definition. $\\left...</description><pubDate>Sat, 25 Apr 2026 21:03:00 GMT</pubDate></item><item><title>How does the existence of a limit imply that a function is uniformly ...</title><link>https://math.stackexchange.com/questions/75491/how-does-the-existence-of-a-limit-imply-that-a-function-is-uniformly-continuous</link><description>Then the theorem that says that any continuous function on a compact set is uniformly continuous can be applied. The arguments above are a workaround this.</description><pubDate>Sun, 19 Apr 2026 23:19:00 GMT</pubDate></item><item><title>real analysis - Continuous bijection from $ (0,1)$ to $ [0,1 ...</title><link>https://math.stackexchange.com/questions/42308/continuous-bijection-from-0-1-to-0-1</link><description>Does there exist a continuous bijection from $(0,1)$ to $[0,1]$? Of course the map should not be a proper map.</description><pubDate>Mon, 20 Apr 2026 10:18:00 GMT</pubDate></item><item><title>real analysis - Continuous mapping on a compact metric space is ...</title><link>https://math.stackexchange.com/questions/110573/continuous-mapping-on-a-compact-metric-space-is-uniformly-continuous</link><description>Basic real analysis should be a source of at least some intuition (which is misleading at times, granted). Can you think of some compact sets in $\mathbf R$? Are continuous functions on those sets uniformly continuous? Can you remember any theorems regarding those? Another idea is to start to try to prove the statement and see whether things start to fall apart.</description><pubDate>Wed, 22 Apr 2026 18:22:00 GMT</pubDate></item><item><title>What does it mean that "every metric is continuous"?</title><link>https://math.stackexchange.com/questions/5074674/what-does-it-mean-that-every-metric-is-continuous</link><description>6 "Every metric is continuous" means that a metric $d$ on a space $X$ is a continuous function in the topology on the product $X \times X$ determined by $d$.</description><pubDate>Sun, 19 Apr 2026 23:19:00 GMT</pubDate></item><item><title>Continuous rational function - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/2467738/continuous-rational-function</link><description>To prove that every rational function is continuous (needless to add "on its domain": it would be redundant, in view of the definition of continuity), knowing that every polynomial is, you just have to apply the theorem:</description><pubDate>Wed, 22 Apr 2026 15:23:00 GMT</pubDate></item><item><title>is argument function continuous? - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/646353/is-argument-function-continuous</link><description>The argument function has domain $ℂ\setminus\ {0\}$ and values in $ℝ/2\piℝ$ (a space homeomorphic to a circle) and as such, it is continuous. It's not well-defined as a function to $ℝ$.</description><pubDate>Sat, 18 Apr 2026 10:20:00 GMT</pubDate></item></channel></rss>