<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title>Bing: Convolution Theorem Problem</title><link>http://www.bing.com:80/search?q=Convolution+Theorem+Problem</link><description>Search results</description><image><url>http://www.bing.com:80/s/a/rsslogo.gif</url><title>Convolution Theorem Problem</title><link>http://www.bing.com:80/search?q=Convolution+Theorem+Problem</link></image><copyright>Copyright © 2026 Microsoft. All rights reserved. These XML results may not be used, reproduced or transmitted in any manner or for any purpose other than rendering Bing results within an RSS aggregator for your personal, non-commercial use. Any other use of these results requires express written permission from Microsoft Corporation. By accessing this web page or using these results in any manner whatsoever, you agree to be bound by the foregoing restrictions.</copyright><item><title>What is convolution, how does it relate to inner product?</title><link>https://math.stackexchange.com/questions/4561334/what-is-convolution-how-does-it-relate-to-inner-product</link><description>My final question is: what is the intuition behind convolution? what is its relation with the inner product? I would appreciate it if you include the examples I gave above and correct me if I am wrong.</description><pubDate>Sat, 25 Apr 2026 20:13:00 GMT</pubDate></item><item><title>definition - What is Convolution? - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/1423817/what-is-convolution</link><description>3 The definition of convolution is known as the integral of the product of two functions $$ (f*g) (t):=\int_ {-\infty}^ {\infty} f (t -\tau)g (\tau)\,\mathrm d\tau$$ But what does the product of the functions give? Why are is it being integrated on negative infinity to infinity? What is the physical significance of the convolution?</description><pubDate>Fri, 24 Apr 2026 13:33:00 GMT</pubDate></item><item><title>Derivative of convolution - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/177239/derivative-of-convolution</link><description>Derivative of convolution Ask Question Asked 13 years, 9 months ago Modified 1 year, 10 months ago</description><pubDate>Sun, 26 Apr 2026 19:00:00 GMT</pubDate></item><item><title>Meaning of convolution? - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/7413/meaning-of-convolution</link><description>I am currently learning about the concept of convolution between two functions in my university course. The course notes are vague about what convolution is, so I was wondering if anyone could giv...</description><pubDate>Sat, 25 Apr 2026 06:01:00 GMT</pubDate></item><item><title>Convolution intuition: clarifying Terence Tao's "blurring"/"fuzz ...</title><link>https://math.stackexchange.com/questions/450147/convolution-intuition-clarifying-terence-taos-blurring-fuzz-interpretation</link><description>On this math.MO post, "What is convolution intuitively?", Terence Tao's answer (in the case where one function is a bump function) involves "blurring" and "fuzz." Could someone clarify his</description><pubDate>Wed, 22 Apr 2026 20:31:00 GMT</pubDate></item><item><title>Why are different operations in mathematics referred to as "convolution"?</title><link>https://math.stackexchange.com/questions/5004105/why-are-different-operations-in-mathematics-referred-to-as-convolution</link><description>Convolution appears in many mathematical contexts, such as signal processing, probability, and harmonic analysis. Each context seems to involve slightly different formulas and operations: In stand...</description><pubDate>Wed, 15 Apr 2026 04:40:00 GMT</pubDate></item><item><title>Proving commutativity of convolution $ (f \ast g) (x) = (g \ast f) (x)$</title><link>https://math.stackexchange.com/questions/4445/proving-commutativity-of-convolution-f-ast-gx-g-ast-fx</link><description>But we can still find valid Laplace transforms of f (t) = t and g (t) = (t^2). If we multiply their Laplace transforms, and then inverse Laplace transform the result, shouldn't the result be a convolution of f and g?</description><pubDate>Sat, 25 Apr 2026 22:58:00 GMT</pubDate></item><item><title>Convolution and multiplication of polynomials is the same?</title><link>https://math.stackexchange.com/questions/1937630/convolution-and-multiplication-of-polynomials-is-the-same</link><description>The term inside the parentheses is the discrete convolution of the coefficients. The fact that convolution shows up when doing products of polynomials is pretty closely tied to group theory and is actually very important for the theory of locally compact abelian groups.</description><pubDate>Sat, 25 Apr 2026 05:47:00 GMT</pubDate></item><item><title>What is the convolution of a function $f$ with a delta function $\delta$?</title><link>https://math.stackexchange.com/questions/1015498/what-is-the-convolution-of-a-function-f-with-a-delta-function-delta</link><description>Explore related questions convolution dirac-delta See similar questions with these tags.</description><pubDate>Fri, 24 Apr 2026 11:03:00 GMT</pubDate></item><item><title>Definition of Convolution - Mathematics Stack Exchange</title><link>https://math.stackexchange.com/questions/4746412/definition-of-convolution</link><description>I am currently studying calculus, but I am stuck with the definition of convolution in terms of constructing the mean of a function. Suppose we have two functions, $f ...</description><pubDate>Wed, 22 Apr 2026 11:48:00 GMT</pubDate></item></channel></rss>